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how many moles of pb(no3)2 are required to generate 12 moles al(no3)3? …

Question

how many moles of pb(no3)2 are required to generate 12 moles al(no3)3? 3pb(no3)2 + 2alcl3 → 3pbcl2 + 2al(no3)3 ? mol pb(no3)2

Explanation:

Step1: Analyze the mole ratio

From the balanced chemical equation \(3Pb(NO_3)_2 + 2AlCl_3
ightarrow3PbCl_2 + 2Al(NO_3)_3\), the mole ratio of \(Pb(NO_3)_2\) to \(Al(NO_3)_3\) is \(3:2\).

Step2: Set up the proportion

Let \(x\) be the moles of \(Pb(NO_3)_2\). Using the mole ratio \(\frac{x}{12}=\frac{3}{2}\).

Step3: Solve for \(x\)

Cross - multiply: \(2x = 3\times12\). Then \(2x=36\), and \(x=\frac{36}{2}=18\).

Answer:

\(18\)