Question

how many kilts of heat are needed to raise the temperature of 15.0 g of aluminum from 21°c to 53°c, if the specific heat of aluminum is 0.90 j/g°c?
a 2008 j
b 294 j
c 716 j
d 432 j

Explanation:

Step1: Calculate the temperature change

$\Delta T=T_{final}-T_{initial}=53^{\circ}C - 21^{\circ}C=32^{\circ}C$

Step2: Use the heat - transfer formula

The formula for heat transfer is $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the temperature change.
Given $m = 15.0g$, $c=0.90J/g^{\circ}C$, and $\Delta T = 32^{\circ}C$
Substitute the values into the formula: $Q=(15.0g)\times(0.90J/g^{\circ}C)\times(32^{\circ}C)$
First, calculate $15.0\times0.90 = 13.5$
Then, $13.5\times32=432J$

Answer:

D. 432 J