Question

how many grams of solute are contained in each solution? be sure each of your answer entries has the correct number of significant figures.
note: reference the si prefixes table for additional information.
part 1 of 2

1. ml of a 3.40 m hno₃ solution

g solute
part 2 of 2
8.00 l of a 3.40 m nano₃ solution
g solute

Explanation:

Part 1 of 2

Step1: Calculate the moles of \(HNO_3\)

Use the formula \(n = C\times V\), where \(C\) is the molarity and \(V\) is the volume in liters.
Given \(C = 3.40\space M\) and \(V=495\space mL=0.495\space L\)
\(n = 3.40\space mol/L\times0.495\space L = 1.683\space mol\)

Step2: Calculate the mass of \(HNO_3\)

The molar mass of \(HNO_3\) is \(M=(1 + 14+3\times16)\space g/mol=63\space g/mol\)
Use the formula \(m = n\times M\)
\(m = 1.683\space mol\times63\space g/mol = 106.029\space g\approx106\space g\) (three significant figures)

Part 2 of 2

Step1: Calculate the moles of \(NaNO_3\)

Use the formula \(n = C\times V\), where \(C = 3.40\space M\) and \(V = 8.00\space L\)
\(n=3.40\space mol/L\times8.00\space L = 27.2\space mol\)

Step2: Calculate the mass of \(NaNO_3\)

The molar mass of \(NaNO_3\) is \(M=(23 + 14+3\times16)\space g/mol = 85\space g/mol\)
Use the formula \(m=n\times M\)
\(m = 27.2\space mol\times85\space g/mol=2312\space g\approx2310\space g\) (three significant figures)

Answer:

• Part 1 of 2: \(106\space g\)
• Part 2 of 2: \(2310\space g\)