Question

how many grams of solute are contained in each solution? be sure each of your answer entries has the correct number of significant figures.
note: reference the si prefixes table for additional information.
part 1 of 2
495 ml of a 3.40 m hno₃ solution
106 g solute
part 2 of 2
8.00 l of a 3.40 m nano₃ solution
2310 g solute

Explanation:

Step1: Calculate moles of solute

Use the formula \(n = M\times V\).
For \(HNO_3\): \(V = 495\space mL=0.495\space L\), \(M = 3.40\space M\). So \(n_{HNO_3}=3.40\space M\times0.495\space L = 1.683\space mol\).
Molar mass of \(HNO_3\): \(M_{HNO_3}=1 + 14+3\times16=63\space g/mol\). Mass \(m = n\times M_{HNO_3}=1.683\space mol\times63\space g/mol = 106.029\space g\approx106\space g\) (3 significant figures).
For \(NaNO_3\): \(V = 8.00\space L\), \(M = 3.40\space M\). So \(n_{NaNO_3}=3.40\space M\times8.00\space L = 27.2\space mol\).
Molar mass of \(NaNO_3\): \(M_{NaNO_3}=23 + 14+3\times16=85\space g/mol\). Mass \(m = n\times M_{NaNO_3}=27.2\space mol\times85\space g/mol = 2312\space g\approx2310\space g\) (3 significant figures).

Answer:

Part 1 of 2: \(106\space g\)
Part 2 of 2: \(2310\space g\)