Question

1. how many grams of carbon are present in 4.08 moles of carbon tetrachloride? 2. how many moles of chlorine are present in 2.65 grams of carbon tetrachloride? use the references to access important values if needed for this question. 628 grams. 0.0172 moles. an error has been detected in your answer. check for typos, miscalculations etc. before submitting your answer. 9 more group attempts remaining. submit answer retry entire group

Explanation:

Step1: Recall molar - mass of carbon

The molar mass of carbon ($C$) is approximately $12.01\ g/mol$.

Step2: Calculate mass of carbon

We use the formula $m = n\times M$, where $n$ is the number of moles and $M$ is the molar - mass. Given $n = 4.08\ mol$ and $M = 12.01\ g/mol$. Then $m=4.08\times12.01 = 49.0008\approx49.0\ g$.

Step3: Recall molar - mass of carbon tetrachloride

The molar - mass of carbon tetrachloride ($CCl_4$) is $M_{CCl_4}=12.01 + 4\times35.45=12.01+141.8 = 153.81\ g/mol$.

Step4: Calculate moles of $CCl_4$

First, find the number of moles of $CCl_4$ in $2.65\ g$. Using the formula $n=\frac{m}{M}$, where $m = 2.65\ g$ and $M = 153.81\ g/mol$. So $n_{CCl_4}=\frac{2.65}{153.81}\approx0.0172\ mol$.

Step5: Determine moles of chlorine

In one mole of $CCl_4$, there are 4 moles of chlorine. So the number of moles of chlorine in $0.0172\ mol$ of $CCl_4$ is $n_{Cl}=4\times0.0172 = 0.0688\ mol$.

Answer:

1. $49.0$ grams
2. $0.0688$ moles