Question

homework: balancing chemical equations and identifying the reaction type
for each of the following equations:
a. balance the chemical equation properly
b. identify which of the six reaction types the chemical reaction falls under (synthesis,
decomposition, single - replacement, neutralization, precipitation or combustion

1. _c2h6 + _o2 → _co2 + _h2o

reaction type:

1. _fe + _s8 → ___fes

reaction type:

1. _h2co3 → _co2 + h2o

reaction type:

1. _agno3 + _al → _al(no3)3 + _ag

reaction type:

1. _hno3 + _ca(oh)2 → _ca(no3)2 + _h2o

reaction type:

1. _na2so4 + _srcl2 → ___nacl + srso4

reaction type:

1. _c4h10 + _o2 → ___co2 + h2o

reaction type:

Explanation:

Step1: Balance the first equation

For \(2C_2H_6+7O_2
ightarrow4CO_2 + 6H_2O\), balance \(C\): \(2C_2H_6\) gives \(4CO_2\). Balance \(H\): \(2C_2H_6\) gives \(6H_2O\). Then balance \(O\): \(7O_2\) gives \(4\times2 + 6\times1=14\) \(O\) atoms.

Step2: Identify reaction type

Combustion reaction (hydrocarbon reacts with \(O_2\)).

Step3: Balance the second equation

For \(8Fe+S_8
ightarrow8FeS\), balance \(S\): \(S_8\) gives \(8FeS\), then balance \(Fe\).

Step4: Identify reaction type

Synthesis reaction (\(Fe\) and \(S_8\) combine).

Step5: Balance the third equation

For \(H_2CO_3
ightarrow CO_2 + H_2O\), already balanced.

Step6: Identify reaction type

Decomposition reaction (\(H_2CO_3\) breaks down).

Step7: Balance the fourth equation

For \(3AgNO_3+Al
ightarrow Al(NO_3)_3+3Ag\), balance \(Ag\) and \(NO_3^-\).

Step8: Identify reaction type

Single - replacement reaction (\(Al\) replaces \(Ag\)).

Step9: Balance the fifth equation

For \(2HNO_3+Ca(OH)_2
ightarrow Ca(NO_3)_2+2H_2O\), balance \(H^+\), \(OH^-\) and \(NO_3^-\).

Step10: Identify reaction type

Neutralization reaction (\(HNO_3\) (acid) and \(Ca(OH)_2\) (base) react).

Step11: Balance the sixth equation

For \(Na_2SO_4+SrCl_2
ightarrow2NaCl + SrSO_4\), balance \(Na\) and \(Cl\).

Step12: Identify reaction type

Precipitation reaction (\(SrSO_4\) precipitates).

Step13: Balance the seventh equation

For \(2C_4H_{10}+13O_2
ightarrow8CO_2 + 10H_2O\), balance \(C\): \(2C_4H_{10}\) gives \(8CO_2\). Balance \(H\): \(2C_4H_{10}\) gives \(10H_2O\). Then balance \(O\): \(13O_2\) gives \(8\times2+10\times1 = 26\) \(O\) atoms.

Step14: Identify reaction type

Combustion reaction (hydrocarbon reacts with \(O_2\)).

Answer:

1. \(2C_2H_6+7O_2

ightarrow4CO_2 + 6H_2O\), Combustion

1. \(8Fe+S_8

ightarrow8FeS\), Synthesis

1. \(H_2CO_3

ightarrow CO_2 + H_2O\), Decomposition

1. \(3AgNO_3+Al

ightarrow Al(NO_3)_3+3Ag\), Single - replacement

1. \(2HNO_3+Ca(OH)_2

ightarrow Ca(NO_3)_2+2H_2O\), Neutralization

1. \(Na_2SO_4+SrCl_2

ightarrow2NaCl + SrSO_4\), Precipitation

1. \(2C_4H_{10}+13O_2

ightarrow8CO_2 + 10H_2O\), Combustion