Question

a gas sample has an initial pressure of 1.18 atm and occupies a volume of 2.0 l. if the pressure is reduced to 0.75 atm while keeping the temperature constant, what will be the new volume of the gas? the new volume is select one select one

Explanation:

Step1: <Apply Boyle's Law>

Boyle's Law is \(P_1V_1 = P_2V_2\), where \(P_1 = 1.18\) atm, \(V_1=2.0\) L, \(P_2 = 0.75\) atm. We need to find \(V_2\).

Step2: <Rearrange the formula to solve for \(V_2\)>

From \(P_1V_1 = P_2V_2\), we get \(V_2=\frac{P_1V_1}{P_2}\).
Substitute the values: \(V_2=\frac{1.18\times2.0}{0.75}\).
Calculate \(1.18\times2.0 = 2.36\).
Then \(V_2=\frac{2.36}{0.75}\approx3.15\) (close to \(3.14\) considering possible rounding differences in the problem - setup).

Answer:

\(3.14\)