Question

a gas mixture contains co, ar and h₂. what is the total pressure of the mixture, if the mole fraction of h₂ is 0.350 and the partial pressure of h₂ is 0.480 atm?
○ 1.37 atm
○ 2.60 atm
○ 4.80 atm
○ 3.50 atm
○ 7.00 atm
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Explanation:

Step1: Recall the formula for partial pressure

The formula relating partial pressure ($P_i$), mole fraction ($X_i$), and total pressure ($P_{total}$) is $P_i = X_i \times P_{total}$.

Step2: Rearrange the formula to solve for $P_{total}$

We can rearrange the formula to $P_{total} = \frac{P_i}{X_i}$.

Step3: Substitute the given values

We know that the partial pressure of $\ce{H_2}$ ($P_{\ce{H_2}}$) is 0.480 atm and the mole fraction of $\ce{H_2}$ ($X_{\ce{H_2}}$) is 0.350. Substituting these values into the formula, we get $P_{total} = \frac{0.480\ \text{atm}}{0.350}$.

Step4: Calculate the total pressure

Performing the division, $\frac{0.480}{0.350} \approx 1.37\ \text{atm}$.

Answer:

1.37 atm