Question

four samples of the same unknown gas g are listed in the table below. rank these samples in increasing order of ideality. that is, select 1 next to the sample of g that will behave least like an ideal gas, and select 4 next to the sample of g that will behave most like an ideal gas.

Explanation:

Step1: Recall the conditions for ideal gas behavior

Ideal gas behavior is favored at low pressure and high temperature. At low pressure, the volume of gas molecules is negligible compared to the total volume of the gas. At high temperature, the intermolecular forces between gas molecules are negligible.

Step2: Compare the samples

• Sample A: High pressure (\(20.0\) atm) and low temperature (\(- 10.0^{\circ}C\)). This sample will deviate the most from ideal gas behavior.
• Sample B: Lower pressure (\(10.0\) atm) than A but same low temperature (\(-10.0^{\circ}C\)).
• Sample C: Same pressure as B (\(10.0\) atm) but higher temperature (\(10.0^{\circ}C\)).
• Sample D: Pressure (\(10.0\) atm) and temperature (\(0.0^{\circ}C\)) between B and C.

Since \(T_C>T_D > T_B=T_A\) (converting temperatures to Kelvin: \(T_A = 263.15\) K, \(T_B=263.15\) K, \(T_D = 273.15\) K, \(T_C=283.15\) K) and \(P_A>P_B = P_C=P_D\). The order of ideality (from least to most) is based on pressure (higher pressure is less ideal) and temperature (lower temperature is less ideal).

Answer:

A: 1, B: 2, D: 3, C: 4