Question

the formula of copper(i) sulfide is: (assume numbers in answer chocies are subscripts) cus cu2s cu2(so4)3 cuso4 cus2

Explanation:

• Copper(I) has a charge of \(+1\).
• Sulfide (\(S^{2 -}\)) has a charge of \(-2\).
• To balance the charges, we need two \(Cu^{+}\) ions for one \(S^{2 -}\) ion.

Answer:

Cu2S