Question

the following chemical reaction takes place in aqueous solution: mgbr₂(aq)+2koh(aq)→mg(oh)₂(s)+2kbr(aq) write the net ionic equation for this reaction.

Explanation:

Step1: Write the complete ionic equation

In aqueous solution, \(MgBr_2\) dissociates as \(Mg^{2 + }(aq)+2Br^{-}(aq)\), \(KOH\) dissociates as \(2K^{+}(aq)+2OH^{-}(aq)\), and \(KBr\) dissociates as \(2K^{+}(aq)+2Br^{-}(aq)\). The complete ionic equation is:
\(Mg^{2 + }(aq)+2Br^{-}(aq)+2K^{+}(aq)+2OH^{-}(aq)\to Mg(OH)_2(s)+2K^{+}(aq)+2Br^{-}(aq)\)

Step2: Cancel out the spectator ions

Spectator ions are \(K^{+}\) and \(Br^{-}\) (they appear on both sides of the equation). After canceling them, we get the net - ionic equation.

Answer:

\(Mg^{2 + }(aq)+2OH^{-}(aq)\to Mg(OH)_2(s)\)