Question

fluorine gas and water vapor react to form hydrogen fluoride gas and oxygen. what volume of oxygen would be produced by this reaction if 12 cm³ of water were consumed? also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits

Explanation:

Step1: Write the balanced chemical equation

$$2F_{2}(g)+2H_{2}O(g) ightarrow 4HF(g)+O_{2}(g)$$

Step2: Use the mole - volume relationship (at the same temperature and pressure, \(V\propto n\), so the ratio of volumes is the same as the ratio of moles)

From the balanced equation, the ratio of \(V(H_{2}O):V(O_{2}) = 2:1\)

Step3: Calculate the volume of \(O_{2}\)

Let \(V(O_{2})\) be the volume of oxygen. Given \(V(H_{2}O)=12\ cm^{3}\)
Using the ratio \(\frac{V(H_{2}O)}{V(O_{2})}=\frac{2}{1}\), then \(V(O_{2})=\frac{V(H_{2}O)}{2}\)
Substitute \(V(H_{2}O) = 12\ cm^{3}\) into the formula: \(V(O_{2})=\frac{12\ cm^{3}}{2}=6.0\ cm^{3}\)

Answer:

\(6.0\ cm^{3}\)