Question

extra problems:

1. how much heat is required to raise the temperature of a 9.46 g sample of iron (specific heat = 0.450 \frac{j}{g\cdot{\hspace{0.167em}\textdegree c}}) from 25.0\textdegree c to 79.8\textdegree c?
2. what is the specific heat capacity of mercury if it requires 167.1 j to change the temperature of 15.0 g of mercury from 25.00\textdegree c to 33.00\textdegree c?

Explanation:

Step1: Recall the heat formula

The formula for heat \(q = mc\Delta T\), where \(m\) is mass, \(c\) is specific heat, \(\Delta T=T_{final}-T_{initial}\)

Step2: Identify the values

Given \(m = 9.46\space g\), \(c=0.450\space\frac{J}{g^{\circ}C}\), \(T_{initial}=25.0^{\circ}C\), \(T_{final} = 79.8^{\circ}C\)

Step3: Calculate \(\Delta T\)

\(\Delta T=79.8 - 25.0=54.8^{\circ}C\)

Step4: Substitute into the formula

\(q=(9.46\space g)\times(0.450\space\frac{J}{g^{\circ}C})\times(54.8^{\circ}C)\)

\(q = 9.46\times0.450\times54.8\)

\(q=9.46\times24.66\)

\(q = 233.38\space J\)

Answer:

\(233\space J\)