Question

extra problems:

1. how much heat is required to raise the temperature of a 9.46 g sample of iron (specific heat = 0.450\\(\frac{j}{g\cdot^\circ c}\\)) from 25.0^\circ c to 79.8^\circ c?

Explanation:

Step1: Calculate the temperature change

$\Delta T=T_{final}-T_{initial}=79.8^{\circ}C - 25.0^{\circ}C=54.8^{\circ}C$

Step2: Use the heat formula

The heat formula is $q = mc\Delta T$, where $m = 9.46g$, $c=0.450\frac{J}{g^{\circ}C}$, and $\Delta T = 54.8^{\circ}C$.
Substitute the values into the formula:
$q=(9.46g)\times(0.450\frac{J}{g^{\circ}C})\times(54.8^{\circ}C)$
First, calculate $9.46\times0.450 = 4.257$
Then, $4.257\times54.8 = 233.3836\approx233J$

Answer:

$233J$