QUESTION IMAGE
Question
extension. identify whether the following compounds are ionic or covalent. then draw lewis structures to represent the bonds they form.
- mgcl₂
- nh₃
- co₂
Step1: Determine bond type for \(MgCl_2\)
\(Mg\) is a metal (Group 2) and \(Cl\) is a non - metal (Group 17). Ionic bonds form between metals and non - metals. So \(MgCl_2\) is ionic.
For Lewis structure of \(MgCl_2\) (in ionic form): \(Mg^{2+}\) and two \(Cl^{-}\). The Lewis structure for \(Cl^{-}\) is \([\colon\ddot{Cl}\colon]^{-}\). So overall it is \(Mg^{2+}[\colon\ddot{Cl}\colon]^{-}[\colon\ddot{Cl}\colon]^{-}\)
Step2: Determine bond type for \(NH_3\)
\(N\) and \(H\) are non - metals. Covalent bonds form between non - metals.
For Lewis structure of \(NH_3\):
- Calculate valence electrons: \(N\) has \(5\) valence electrons and each \(H\) has \(1\) valence electron. Total valence electrons \(=5 + 3\times1=8\)
- \(N\) is the central atom. \(N\) forms three single bonds with \(H\) atoms. And there is one lone pair on \(N\). The Lewis structure is \(
\) (or more accurately \(\ce{H-\underset{H}{\overset{H}{\underset{\mid}{\overset{\mid}{N}}}-\colon}}\))
Step3: Determine bond type for \(CO_2\)
\(C\) and \(O\) are non - metals. Covalent bonds form between non - metals.
For Lewis structure of \(CO_2\):
- Calculate valence electrons: \(C\) has \(4\) valence electrons and each \(O\) has \(6\) valence electrons. Total valence electrons \(=4+2\times6 = 16\)
- \(C\) is the central atom. \(C\) forms double bonds with each \(O\) atom. The Lewis structure is \(\colon\ddot{O}\colon = C=\colon\ddot{O}\colon\)
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- \(MgCl_2\): Ionic. Lewis structure: \(Mg^{2+}[\colon\ddot{Cl}\colon]^{-}[\colon\ddot{Cl}\colon]^{-}\)
- \(NH_3\): Covalent. Lewis structure: \(\ce{H-\underset{H}{\overset{H}{\underset{\mid}{\overset{\mid}{N}}}-\colon}}\)
- \(CO_2\): Covalent. Lewis structure: \(\colon\ddot{O}\colon = C=\colon\ddot{O}\colon\)