Question

the equivalent mass of kmno₄ in a high basic medium is equal to its molar mass dividing by …………
o a 5
b. none of them
o c 1
d 3
clear my choice

Explanation:

Step1: Determine the reaction of \(KMnO_4\) in a highly basic medium

In a highly basic medium, the reaction of \(KMnO_4\) is \(MnO_4^-+e^-\to MnO_4^{2 -}\).

Step2: Calculate the change in oxidation state

The oxidation state of \(Mn\) in \(MnO_4^-\) is \(+7\) and in \(MnO_4^{2-}\) is \(+6\). The change in oxidation state (\(\Delta n\)) is \(1\) (since \(7 - 6=1\)).

Step3: Use the formula for equivalent mass

The formula for equivalent mass (\(E\)) is \(E=\frac{Molar\ mass(M)}{Change\ in\ oxidation\ state(\Delta n)}\). Here, \(\Delta n = 1\).

Answer:

C. 1