Question

the empirical formula doesnt tell us how many atoms are in the molecule but the molecular formula would...
at this point, we only know the relative proportion of elements in the compound. c4h5n2o is the empirical formula. it does not reflect the actual number of atoms in a molecule of the substance. so you have the empirical formula for the compound, thats great. but we still dont know what the molecular formula is.
the team has run some other tests and now knows the molecular weight of the compound is 194.2 amu.
does the weight of the empirical formula you generated match the molecular weight of the compound?
what is the empirical formula weight?
c4h5n2o1 = amu

Explanation:

Step1: Find atomic weights

Atomic weight of \(C = 12.01\) amu, \(H=1.008\) amu, \(N = 14.01\) amu, \(O=16.00\) amu.

Step2: Calculate empirical formula weight

For \(C_4H_5N_2O\):

$$
LATEXBLOCK0
$$

Answer:

\(97.1\) amu