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electron configuration objectives: draw an orbital diagram for a given …

Question

electron configuration
objectives:
draw an orbital diagram for a given element using up and down arrows to represent spin.
write an electron configuration for a given element.
a. draw the orbital diagrams for the following ions. this will be the same orbital diagrams as a neutral atom except youve added or subtracted some arrows to represent the electrons that were added or subtracted.
na1+
ca2+
o2-
b. write the electron configuration for the following ions.

  1. be2+
  2. li1+
  3. f1-
  4. br1-
  5. mg2+
  6. cl1-
  7. k+
  8. fe2+

Explanation:

Step1: Determine the number of electrons in each ion

  • For \(Be^{2 +}\): Beryllium has an atomic number of \(4\). \(Be^{2+}\) has \(4 - 2=2\) electrons.
  • For \(Li^{1+}\): Lithium has an atomic number of \(3\). \(Li^{1+}\) has \(3 - 1 = 2\) electrons.
  • For \(F^{1-}\): Fluorine has an atomic number of \(9\). \(F^{1-}\) has \(9+1 = 10\) electrons.
  • For \(Br^{1-}\): Bromine has an atomic number of \(35\). \(Br^{1-}\) has \(35 + 1=36\) electrons.
  • For \(Mg^{2+}\): Magnesium has an atomic number of \(12\). \(Mg^{2+}\) has \(12- 2=10\) electrons.
  • For \(Cl^{1-}\): Chlorine has an atomic number of \(17\). \(Cl^{1-}\) has \(17+1 = 18\) electrons.
  • For \(K^{+}\): Potassium has an atomic number of \(19\). \(K^{+}\) has \(19 - 1=18\) electrons.
  • For \(Fe^{2+}\): Iron has an atomic number of \(26\). \(Fe^{2+}\) has \(26-2 = 24\) electrons.

Step2: Write the electron configuration using the Aufbau principle

  • \(Be^{2+}\): \(1s^{2}\)
  • \(Li^{1+}\): \(1s^{2}\)
  • \(F^{1-}\): \(1s^{2}2s^{2}2p^{6}\)
  • \(Br^{1-}\): \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}\)
  • \(Mg^{2+}\): \(1s^{2}2s^{2}2p^{6}\)
  • \(Cl^{1-}\): \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)
  • \(K^{+}\): \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)
  • \(Fe^{2+}\): \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{0}3d^{6}\) (Electrons are removed from the \(4s\) orbital first as per the rule for transition - metal cations)

Answer:

  1. \(Be^{2+}\): \(1s^{2}\)
  2. \(Li^{1+}\): \(1s^{2}\)
  3. \(F^{1-}\): \(1s^{2}2s^{2}2p^{6}\)
  4. \(Br^{1-}\): \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}\)
  5. \(Mg^{2+}\): \(1s^{2}2s^{2}2p^{6}\)
  6. \(Cl^{1-}\): \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)
  7. \(K^{+}\): \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)
  8. \(Fe^{2+}\): \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{6}\)