Question

during a titration of hcl$_{(aq)}$ with naoh$_{(aq)}$, the naoh$_{(aq)}$ behaves as i and the hcl$_{(aq)}$ behaves as ii .
the statement above is completed by the information in:

i | a base , ii | a base

i | a base , ii | an acid

i | an acid , ii | an acid

i | an acid , ii | a base

Explanation:

In acid - base chemistry, NaOH (sodium hydroxide) is a strong base as it donates hydroxide ions (\(OH^-\)) in solution. HCl (hydrochloric acid) is a strong acid as it donates hydrogen ions (\(H^+\)) in solution. So in the titration of HCl with NaOH, NaOH behaves as a base and HCl behaves as an acid.

Answer:

i | a base, ii | an acid