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draw (on paper) lewis structures for the carbonate ion and sulfur diflu…

Question

draw (on paper) lewis structures for the carbonate ion and sulfur difluoride.
how many equivalent lewis structures are necessary to describe the bonding in co₃²⁻?
how many equivalent lewis structures are necessary to describe the bonding in sf₂?
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Explanation:

For $\boldsymbol{\ce{CO_3^{2-}}}$ (Carbonate ion):

Step1: Analyze the carbonate ion structure

The carbonate ion ($\ce{CO_3^{2-}}$) has a central carbon atom bonded to three oxygen atoms. The carbon atom is $sp^2$ hybridized, and the three $\ce{C - O}$ bonds are equivalent due to resonance. The resonance in carbonate ion involves the delocalization of the negative charge over the three oxygen atoms.

Step2: Determine the number of equivalent Lewis structures

To represent the resonance in $\ce{CO_3^{2-}}$, we need three equivalent Lewis structures. In each structure, one of the $\ce{C - O}$ bonds is a double bond, and the other two are single bonds, but the double bond can be on any of the three oxygen atoms, leading to three equivalent resonance (Lewis) structures.

For $\boldsymbol{\ce{SF_2}}$ (Sulfur difluoride):

Step1: Analyze the sulfur difluoride structure

Sulfur difluoride ($\ce{SF_2}$) has a central sulfur atom bonded to two fluorine atoms. The sulfur atom has two lone pairs of electrons (in addition to the two $\ce{S - F}$ bonds). The structure of $\ce{SF_2}$ is a bent molecular geometry (due to the lone pairs), and there is no resonance because the bonding is straightforward (two single bonds between $\ce{S}$ and $\ce{F}$ and two lone pairs on $\ce{S}$).

Step2: Determine the number of equivalent Lewis structures

Since there is no resonance (the electron distribution is fixed with two $\ce{S - F}$ single bonds and two lone pairs on $\ce{S}$), only one Lewis structure is needed to describe the bonding in $\ce{SF_2}$.

Answer:

For $\ce{CO_3^{2-}}$: $\boldsymbol{3}$
For $\ce{SF_2}$: $\boldsymbol{1}$