Question

1. drag and drop the reactions with the equations.

so₃ + h₂o → h₂so₄

caco₃ → cao + co₂

pb + feso₄ → pbso₄ + fe

mgcl₂ + li₂co₃ → mgco₃ + 2licl

c₆h₁₂ + 9o₂ → 6co₂ + 6h₂o

Explanation:

1. For $\ce{SO_{3} + H_{2}O \to H_{2}SO_{4}}$: A synthesis reaction combines substances into one. Here, $\ce{SO_{3}}$ and $\ce{H_{2}O}$ form $\ce{H_{2}SO_{4}}$, so it's synthesis.
2. For $\ce{CaCO_{3} \to CaO + CO_{2}}$: A decomposition reaction breaks a compound into simpler substances. $\ce{CaCO_{3}}$ breaks into $\ce{CaO}$ and $\ce{CO_{2}}$, so it's decomposition.
3. For $\ce{Pb + FeSO_{4} \to PbSO_{4} + Fe}$: A single replacement reaction has one element replacing another in a compound. $\ce{Pb}$ replaces $\ce{Fe}$ in $\ce{FeSO_{4}}$, so it's single replacement.
4. For $\ce{MgCl_{2} + Li_{2}CO_{3} \to MgCO_{3} + 2LiCl}$: A double replacement reaction swaps ions between two compounds. $\ce{Mg^{2+}}$ and $\ce{Li^{+}}$ swap with $\ce{Cl^{-}}$ and $\ce{CO_{3}^{2-}}$, so it's double replacement.
5. For $\ce{C_{6}H_{12} + 9O_{2} \to 6CO_{2} + 6H_{2}O}$: A combustion reaction involves a substance reacting with $\ce{O_{2}}$ to produce $\ce{CO_{2}}$ and $\ce{H_{2}O}$ (for hydrocarbons), so this is combustion.

Answer:

$\ce{SO_{3} + H_{2}O \to H_{2}SO_{4}}$: synthesis
$\ce{CaCO_{3} \to CaO + CO_{2}}$: decomposition
$\ce{Pb + FeSO_{4} \to PbSO_{4} + Fe}$: single replacement
$\ce{MgCl_{2} + Li_{2}CO_{3} \to MgCO_{3} + 2LiCl}$: double replacement
$\ce{C_{6}H_{12} + 9O_{2} \to 6CO_{2} + 6H_{2}O}$: combustion