Question

double replacement
– two compounds switch parts with one another.

• ( \text{agno}_3 + \text{k}_2\text{so}_4

ightarrow \text{ag}_2\text{so}_4 + \text{kno}_3 )

Explanation:

Step1: Balance the Ag atoms

On the left, we have 1 Ag in $AgNO_3$. On the right, we have 2 Ag in $Ag_2SO_4$. So we put a coefficient of 2 in front of $AgNO_3$:

$$2AgNO_3 + K_2SO_4 ightarrow Ag_2SO_4 + KNO_3$$

Step2: Balance the K atoms

Now, on the left, we have 2 K in $K_2SO_4$. On the right, we have 1 K in $KNO_3$. So we put a coefficient of 2 in front of $KNO_3$:

$$2AgNO_3 + K_2SO_4 ightarrow Ag_2SO_4 + 2KNO_3$$

Step3: Check other atoms

• For N: Left has 2 N (from $2AgNO_3$), right has 2 N (from $2KNO_3$).
• For S: Left has 1 S (from $K_2SO_4$), right has 1 S (from $Ag_2SO_4$).
• For O: Left has $2\times3 + 4 = 10$ O, right has $4 + 2\times3 = 10$ O. All atoms are balanced.

Answer:

The balanced chemical equation is $\boldsymbol{2AgNO_3 + K_2SO_4
ightarrow Ag_2SO_4 + 2KNO_3}$