Question

directions: fill in the missing information for a given element.

	name	total # electrons	electron configuration
2.	chlorine		noble gas notation:
3.**	nitrogen		orbital notation:

teacher use only | score %
1/6 | 17
2/6 | 33
3/6 | 50
4/6 | 67
5/6 | 83
6/6 | 100

Explanation:

Step1: Determine number of electrons for oxygen

Oxygen has an atomic number of 8, so total electrons = 8.

Step2: Write full - electron configuration for oxygen

Using the Aufbau principle, the electron configuration is $1s^{2}2s^{2}2p^{4}$.

Step3: Determine number of electrons for chlorine

Chlorine has an atomic number of 17, so total electrons = 17.

Step4: Write noble - gas notation for chlorine

The noble gas before chlorine is neon (Ne). Neon has 10 electrons. So the noble - gas notation is $[Ne]3s^{2}3p^{5}$.

Step5: Determine number of electrons for nitrogen

Nitrogen has an atomic number of 7, so total electrons = 7.

Step6: Write orbital notation for nitrogen

For nitrogen ($1s^{2}2s^{2}2p^{3}$), the orbital notation is:
1s: $\uparrow\downarrow$
2s: $\uparrow\downarrow$
2p: $\uparrow$ $\uparrow$ $\uparrow$

Answer:

1. Name: Oxygen, Total # electrons: 8, Electron Configuration (Full): $1s^{2}2s^{2}2p^{4}$
2. Name: Chlorine, Total # electrons: 17, Electron Configuration (Noble Gas Notation): $[Ne]3s^{2}3p^{5}$
3. Name: Nitrogen, Total # electrons: 7, Electron Configuration (Orbital Notation):

1s: $\uparrow\downarrow$
2s: $\uparrow\downarrow$
2p: $\uparrow$ $\uparrow$ $\uparrow$