Question

the diagram below is a model of two solutions. each ball represents one particle of solute. solvent volume: 45 ml solvent volume: 50 ml solution a solution b which solution has a higher concentration of pink particles? solution a solution b neither; their concentrations are the same

Explanation:

Step1: Calculate the concentration of pink particles in Solution A

Concentration \(C=\frac{\text{Number of solute particles}}{\text{Volume of solvent}}\). In Solution A, the number of pink particles \(n = 3\), and the volume of solvent \(V=45\space mL\). So \(C_A=\frac{3}{45}=\frac{1}{15}\space particles/mL\)

Step2: Calculate the concentration of pink particles in Solution B

In Solution B, the number of pink particles \(n = 8\), and the volume of solvent \(V = 50\space mL\). So \(C_B=\frac{8}{50}=\frac{4}{25}\space particles/mL\)

Step3: Compare the two concentrations

Find a common denominator. \(\frac{1}{15}=\frac{1\times5}{15\times5}=\frac{5}{75}\) and \(\frac{4}{25}=\frac{4\times3}{25\times3}=\frac{12}{75}\). Since \(\frac{12}{75}>\frac{5}{75}\) (i.e., \(C_B > C_A\))

Answer:

Solution B