Question

determine the number of particles in the 2.50 mol sample of nacl. 1 mol nacl = 6.02 x 10^{23} particles nacl 2.50 mol nacl = ? x 10^{} particles nacl enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to three decimal places.

Explanation:

Step1: Set up the proportion

We know that \(1\space mol\space NaCl = 6.02\times10^{23}\space particles\). Let \(x\) be the number of particles in \(2.50\space mol\space NaCl\). Then the proportion is \(\frac{x}{2.50}=\frac{6.02\times 10^{23}}{1}\).

Step2: Solve for \(x\)

Multiply both sides of the equation by \(2.50\). So \(x=(2.50)\times(6.02\times 10^{23})\). Using the rule \(a\times(b\times 10^{n})=(a\times b)\times10^{n}\), we have \(x = 15.05\times10^{23}\). In scientific notation \(a\times 10^{n}\) where \(1\leqslant a<10\), we rewrite \(15.05\times10^{23}\) as \(1.505\times 10^{24}\).

Answer:

The coefficient is \(1.51\) (rounded to two decimal places) and the exponent is \(24\).