Question

1. a container of oxygen has a volume of 20.0 ml and a pressure of 4.00 atm. if the pressure of the oxygen gas is reduced to 6.00 atm and the temperature is kept constant, what is the new volume of the oxygen gas?

Explanation:

Step1: Identificar la ley de Boyle

Para un gas a temperatura constante, $P_1V_1 = P_2V_2$.

Step2: Asignar valores

$P_1 = 4.00$ atm, $V_1=20.0$ mL, $P_2 = 6.00$ atm, $V_2$ es lo que se busca.

Step3: Despejar $V_2$

$V_2=\frac{P_1V_1}{P_2}$.

Step4: Calcular

$V_2=\frac{4.00\text{ atm}\times20.0\text{ mL}}{6.00\text{ atm}}=\frac{80.0}{6.00}\text{ mL}\approx13.3$ mL.

Answer:

$13.3$ mL