Question

construct the expression for ksp for solid ba3(po4)2 in aqueous solution ba3(po4)2(s) 3 ba2+(aq) + 2 po43- (aq) based on your knowledge of how the solid will dissociate in aqueous solution, construct the expression for the solubility constant, ksp. each reaction participant must be represented by one tile. ksp =

Explanation:

Step1: Recall the formula for solubility product constant

For a general dissolution reaction \(A_xB_y(s)
ightleftharpoons xA^{y +}(aq)+yB^{x -}(aq)\), the solubility product constant \(K_{sp}=[A^{y +}]^x[B^{x -}]^y\).

Step2: Identify \(x\) and \(y\) for \(Ba_3(PO_4)_2\)

In the reaction \(Ba_3(PO_4)_2(s)
ightleftharpoons3Ba^{2 +}(aq)+2PO_4^{3 -}(aq)\), \(x = 3\) (the coefficient of \(Ba^{2+}\)) and \(y=2\) (the coefficient of \(PO_4^{3 -}\)).

Step3: Write the \(K_{sp}\) expression

Substitute \(x = 3\) and \(y = 2\) into the \(K_{sp}\) formula. So \(K_{sp}=[Ba^{2 +}]^3[PO_4^{3 -}]^2\).

Answer:

\(K_{sp}=[Ba^{2 +}]^3[PO_4^{3 -}]^2\)