Question

considering the following precipitation reaction: pb(no₃)₂(aq) + 2ki(aq)→pbi₂(s) + 2kno₃(aq) which ion(s) would not be present in the net ionic equation? a k⁺ and no₃⁻ b k⁺ and i⁻ c pb²⁺ and no₃⁻ d k⁺ and pb²⁺

Explanation:

Step1: Write complete ionic equation

$Pb^{2 +}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+2I^{-}(aq)
ightarrow PbI_{2}(s)+2K^{+}(aq)+2NO_{3}^{-}(aq)$

Step2: Identify spectator ions

Spectator ions are those that appear on both sides of the equation. Here, $K^{+}$ and $NO_{3}^{-}$ are spectator ions.

Step3: Write net - ionic equation

Net - ionic equation is obtained by removing spectator ions: $Pb^{2 +}(aq)+2I^{-}(aq)
ightarrow PbI_{2}(s)$

Answer:

A. $K^{+}$ and $NO_{3}^{-}$