Question

2 a compound with the molecular formula c₂h₄o₂ has the empirical formula

∘ c₂h₄o₂

∘ cho

∘ ch₄o

∘ ch₂o

Explanation:

Step1: Recall Empirical Formula Definition

The empirical formula is the simplest whole - number ratio of atoms in a compound. For a compound with molecular formula \(C_xH_yO_z\), we find the greatest common divisor (GCD) of \(x\), \(y\), and \(z\) and divide each subscript by it.
Given the molecular formula \(C_2H_4O_2\). The subscripts are 2 (for C), 4 (for H), and 2 (for O).

Step2: Find GCD and Simplify

The GCD of 2, 4, and 2 is 2.
Divide each subscript by 2:

• For C: \(\frac{2}{2}=1\)
• For H: \(\frac{4}{2} = 2\)
• For O: \(\frac{2}{2}=1\)

So the empirical formula is \(CH_2O\).

Answer:

\(CH_2O\) (assuming one of the options is \(CH_2O\), as per the calculation. If we consider the options, we need to match this formula. Looking at the options, the one with \(CH_2O\) is the correct empirical formula for \(C_2H_4O_2\))