Question

complete the vsepr table.
geometry domains angle
? 180°
3 bonding
bent 2 bonding / 1 lone pair
4 bonding
trigonal pyramidal
bent <109.5°
trigonal planar linear
tetrahedral planar tetrahedral

Explanation:

Step1: Recall VSEPR geometry for 180° angle

According to VSEPR theory, when the bond - angle is \(180^{\circ}\), the electron - domain geometry is linear.

Step2: Determine geometry for 3 bonding domains

For 3 bonding domains (no lone pairs), the geometry is trigonal planar. The bond - angle for trigonal planar geometry is \(120^{\circ}\).

Step3: Find bond - angle for bent (2 bonding/1 lone pair)

For a bent molecule with 2 bonding and 1 lone pair (total of 3 electron domains, similar to trigonal planar electron - domain geometry but with one lone pair), the bond - angle is approximately \(120^{\circ}\).

Step4: Identify geometry for 4 bonding domains

When there are 4 bonding domains (no lone pairs), the geometry is tetrahedral. The bond - angle in a tetrahedral geometry is \(109.5^{\circ}\).

Step5: Determine electron domains for trigonal pyramidal

A trigonal pyramidal geometry has 3 bonding and 1 lone pair, so the total number of electron domains is \(4\). The bond - angle is less than \(109.5^{\circ}\) (due to the repulsion from the lone pair).

Step6: Find electron domains for bent (\(< 109.5^{\circ}\))

A bent geometry with a bond - angle less than \(109.5^{\circ}\) has 2 bonding and 2 lone pairs (total of 4 electron domains).

Answer:

Geometry	Domains	Angle
trigonal planar	3 bonding	\(120^{\circ}\)
bent	2 bonding / 1 lone pair	\(120^{\circ}\)
tetrahedral	4 bonding	\(109.5^{\circ}\)
trigonal pyramidal	3 bonding / 1 lone pair	\(< 109.5^{\circ}\)
bent	2 bonding / 2 lone pairs	\(< 109.5^{\circ}\)