QUESTION IMAGE
Question
complete this table.
| name | empirical formula |
|---|---|
| barium sulfide |
Step1: Determine charge of ions for chromium(II) iodide
Chromium(II) has a charge of $Cr^{2 + }$ and iodide is $I^{-}$. To balance the charges, we need 2 iodide ions for 1 chromium(II) ion.
Step2: Write empirical formula for chromium(II) iodide
The empirical formula is $CrI_{2}$.
Step3: Determine charge of ions for barium sulfide
Barium has a charge of $Ba^{2+}$ and sulfide is $S^{2 - }$. The charges balance in a 1:1 ratio.
Step4: Write empirical formula for barium sulfide
The empirical formula is $BaS$.
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| name | empirical formula |
|---|---|
| barium sulfide | $BaS$ |