Question

complete the missing components of the products in the acid hydrolysis of methyl butanoate below. for the first product fill in the remaining part of the acid formula, and for the second fill in the remaining part of the alcohol formula.
provide your answer below:
methyl butanoate + h₂o ⇌ □cooh + □oh

Explanation:

Step1: Analyze ester structure

Esters have the general formula $\text{RCOOR}'$. Methyl butanoate has the structure $\text{CH}_3\text{CH}_2\text{CH}_2\text{COOCH}_3$.

Step2: Determine acid part

In acid hydrolysis of ester, the acid part comes from the acyl group ($\text{RCO}-$). For methyl butanoate, the acyl group is $\text{CH}_3\text{CH}_2\text{CH}_2\text{CO}-$, so the acid is $\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}$ (butanoic acid).

Step3: Determine alcohol part

The alcohol part comes from the $\text{OR}'$ group. Here, $\text{OR}'$ is $\text{OCH}_3$, so the alcohol is $\text{CH}_3\text{OH}$ (methanol).

Answer:

$\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH} + \text{CH}_3\text{OH}$