Question

compare the freezing and boiling points of water.
°f °c k
freezing: __ __
boiling: __ __

Explanation:

Step1: Freezing point conversion

• Celsius: The freezing point of water is \(0^{\circ}C\).
• Fahrenheit: Use the formula \(F=\frac{9}{5}C + 32\). Substitute \(C = 0\), then \(F=\frac{9}{5}\times0+32=32^{\circ}F\).
• Kelvin: Use the formula \(K = C+ 273.15\). Substitute \(C = 0\), then \(K=0 + 273.15=273.15\space K\).

Step2: Boiling point conversion

• Celsius: The boiling point of water is \(100^{\circ}C\).
• Fahrenheit: Use the formula \(F=\frac{9}{5}C + 32\). Substitute \(C = 100\), then \(F=\frac{9}{5}\times100+32=180 + 32=212^{\circ}F\).
• Kelvin: Use the formula \(K = C+ 273.15\). Substitute \(C = 100\), then \(K=100+273.15 = 373.15\space K\).

Answer:

Freezing: \(32^{\circ}F\), \(0^{\circ}C\), \(273.15\space K\)
Boiling: \(212^{\circ}F\), \(100^{\circ}C\), \(373.15\space K\)