Question

combining.

1. filter the contents of the beaker, by using a funnel and erlenmeyer flask with the filter paper shaped into a cone. do not overflow the filter paper and use a rinse bottle to be sure to get everything out of the beaker. after filtering, place the filter paper on a watch glass and place it in the oven to dry overnight.
2. you are now ready to clean up any spills with a wet paper towel and dispose of them in the trash. thoroughly wash your glassware, work area, and hands when finished.

day 2: remove your sample from the oven and allow it to cool before massing. mass the copper and record the value in the data table. dispose of the copper in container provided. clean up as needed.
data table: (units!)
a. mass of 100 ml beaker + copper (ii) sulfate | 60.829 g
b. mass of empty 100 - ml beaker. | 48.287 g
c. mass of copper (ii) sulfate used. | 12.542 g
d. mass of iron filings used. | 2.322 g
e. mass of filter paper and copper. | 1.428 g
f. mass of dry filter paper with name(s). | 1.033 g
g. mass of copper produced. | 2.477 g
calculations: (show work using correct units and sig. figs.!)

1. calculate the number of moles of copper produced.
2. calculate the number of moles of iron reacted.
3. find the whole number ratio of moles of iron to moles of copper.

\\(\frac{moles\\ fe}{moles\\ cu}=\\)

Explanation:

Step1: Calculate moles of copper

Use the formula \(n=\frac{m}{M}\), where \(m\) is mass and \(M\) is molar mass (\(M_{Cu}=63.55\ g/mol\)). Given \(m_{Cu} = 2.477\ g\).
\(n_{Cu}=\frac{2.477\ g}{63.55\ g/mol}\)

Step2: Calculate moles of iron

Assume the reaction \(Fe + CuSO_4=FeSO_4 + Cu\). Mole ratio \(Fe:Cu = 1:1\). But if we use \(m_{Fe}=2.322\ g\) and \(M_{Fe} = 55.85\ g/mol\), \(n_{Fe}=\frac{2.322\ g}{55.85\ g/mol}\)

Step3: Find mole ratio

\(\frac{n_{Fe}}{n_{Cu}}=\frac{\frac{2.322}{55.85}}{\frac{2.477}{63.55}}\)

Answer:

1. \(n_{Cu}=\frac{2.477\ g}{63.55\ g/mol}\approx0.0390\ mol\)
2. \(n_{Fe}=\frac{2.322\ g}{55.85\ g/mol}\approx0.0416\ mol\)
3. \(\frac{n_{Fe}}{n_{Cu}}=\frac{\frac{2.322}{55.85}}{\frac{2.477}{63.55}}=\frac{2.322\times63.55}{2.477\times55.85}\approx1.06\approx1:1\)