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click the link here to open the atom - building interactive, and click …

Question

click the link here to open the atom - building interactive, and click the atom square. use the interactive to answer the following questions. note: keep all atoms neutral (net charge = 0) for this exercise. be sure to select the \plus\ sign to expand the element, mass number, and net charge windows. make a he atom with a mass of 4. how many protons did you put in the nucleus? make a li atom with a mass number of 7. how many electrons did you place in the outermost orbital (ring)? make a n atom with a mass number of 14. how many neutrons are in the nucleus? make a b atom with a mass number of 11. how many electrons did you put in the second orbital (ring)? done

Explanation:

Question 1: He atom with mass of 4

Step1: Recall atomic number of He

The atomic number of He (helium) is 2. The atomic number \(Z\) is equal to the number of protons.

Step2: Conclusion

Since \(Z = 2\) for He, the number of protons is 2.

Question 2: Li atom with mass number 7

Step1: Recall atomic number of Li

The atomic number of Li (lithium) is 3. For a neutral atom, the number of electrons \(e^-\) equals the number of protons (\(Z\)). So, there are 3 electrons.

Step2: Electron - shell configuration

The first shell (K - shell) can hold a maximum of 2 electrons. The remaining \(3 - 2=1\) electron goes to the outermost (L - shell) orbital.

Question 3: N atom with mass number 14

Step1: Recall atomic number of N

The atomic number of N (nitrogen) is 7. The mass number \(A\) is given by \(A=Z + N\), where \(N\) is the number of neutrons.

Step2: Calculate number of neutrons

We know \(A = 14\) and \(Z = 7\). Using the formula \(N=A - Z\), we substitute the values: \(N = 14-7=7\).

Question 4: B atom with mass number 11

Step1: Recall atomic number of B

The atomic number of B (boron) is 5. For a neutral atom, the number of electrons \(e^-\) equals the number of protons (\(Z = 5\)).

Step2: Electron - shell configuration

The first shell (K - shell) can hold 2 electrons. The second shell (L - shell) will hold the remaining \(5 - 2 = 3\) electrons.

Answer:

  1. 2
  2. 1
  3. 7
  4. 3