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a chemist prepares a solution of zinc oxalate (znc₂o₄) by weighing out …

Question

a chemist prepares a solution of zinc oxalate (znc₂o₄) by weighing out 6.701 g of zinc oxalate into a 400. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in g/ml of the chemists zinc oxalate solution. be sure your answer has the correct number of significant digits.

Explanation:

Step1: Recall the formula for concentration (mass/volume)

Concentration \( C=\frac{m}{V} \), where \( m \) is mass and \( V \) is volume.

Step2: Substitute the given values

Given \( m = 6.701\ g \) and \( V=400.\ mL \). Then \( C=\frac{6.701\ g}{400.\ mL} \).

Step3: Perform the division

\( C = 0.0167525\ g/mL\approx0.0168\ g/mL \) (rounded to three significant digits as 6.701 has four and 400. has three, and we go by the least number of significant digits in division - three from 400.).

Answer:

\( 0.0168\ g/mL \)