Question

a chemist adds 425.0 ml of a 7.85 g/dl aluminum chloride (alcl₃) solution to a flask.
calculate the mass in grams of aluminum chloride the chemist has added to the flask. be sure your answer has the correct number of
significant digits.

Explanation:

Step1: Convert volume from mL to dL

Since \(1\space dL = 100\space mL\), then \(V=425.0\space mL\times\frac{1\space dL}{100\space mL}=4.250\space dL\)

Step2: Calculate mass using concentration formula

The formula for mass \(m\) is \(m = C\times V\), where \(C = 7.85\space g/dL\) and \(V = 4.250\space dL\). So \(m=7.85\space g/dL\times4.250\space dL\)

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Considering significant figures (three significant figures from \(7.85\)), \(m = 33.4\space g\)

Answer:

\(33.4\space g\)