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check your learning 1. explain why the boiling point of water is a char…

Question

check your learning

  1. explain why the boiling point of water is a characteristic physical property, but the temperature and the volume of a glass of water are not.
  2. which properties of mercury make it a good material to use in a thermostat?
  3. if you could place a piece of solid silver into a container of liquid silver, would it float or sink? explain your answer.
  4. a sample of pure iron has a mass of 5.00 g. calculate its volume.
  5. a metal with a mass of 71.68 g occupies a volume of 8.00 cm³. calculate the density of the metal. using table 1 on page 193, determine the identity of the metal.
  6. a sample of pure copper has a volume of 3.75 cm³. calculate its mass.
  7. a metal with a mass of 1.00 kg occupies a volume of 370 cm³. calculate the density of the metal. using table 1 on page 193, determine the identity of the metal.

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume.

Step2: Solve for volume of iron

The density of pure iron $
ho_{iron}=7.87\ g/cm^{3}$. Given $m = 5.00\ g$, from $
ho=\frac{m}{V}$, we can solve for $V$. Rearranging gives $V=\frac{m}{
ho}$. Substituting values: $V=\frac{5.00\ g}{7.87\ g/cm^{3}}\approx0.635\ cm^{3}$.

Step3: Solve for density of metal in question 5

Given $m = 71.68\ g$ and $V = 8.00\ cm^{3}$, using $
ho=\frac{m}{V}$, we have $
ho=\frac{71.68\ g}{8.00\ cm^{3}} = 8.96\ g/cm^{3}$. Looking up in the table (not provided here but assuming standard density - metal tables), this density is close to that of copper.

Step4: Solve for mass of copper

The density of pure copper $
ho_{copper}=8.96\ g/cm^{3}$. Given $V = 3.75\ cm^{3}$, from $
ho=\frac{m}{V}$, we can solve for $m$. Rearranging gives $m=
ho V$. Substituting values: $m = 8.96\ g/cm^{3}\times3.75\ cm^{3}=33.6\ g$.

Step5: Solve for density of metal in question 7

First convert mass to grams: $m = 1.00\ kg=1000\ g$. Given $V = 370\ cm^{3}$, using $
ho=\frac{m}{V}$, we have $
ho=\frac{1000\ g}{370\ cm^{3}}\approx2.70\ g/cm^{3}$. Looking up in the table (not provided here but assuming standard density - metal tables), this density is close to that of aluminum.

Answer:

  1. The volume of the pure - iron sample is approximately $0.635\ cm^{3}$.
  2. The density of the metal is $8.96\ g/cm^{3}$, and it is likely copper.
  3. The mass of the pure - copper sample is $33.6\ g$.
  4. The density of the metal is approximately $2.70\ g/cm^{3}$, and it is likely aluminum.