Question

calculate the volume in liters of a 0.078 mol/l silver nitrate solution that contains 6.00 mol of silver nitrate (agno₃). be sure your answer has the correct number of significant digits.

Explanation:

Step1: Recall molarity formula

Molarity ($M$) is defined as $M=\frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume in liters. We need to solve for $V$. Rearranging the formula gives $V = \frac{n}{M}$.

Step2: Substitute values

We are given that $n = 6.00$ mol and $M=0.078$ mol/L. Substituting these values into the formula $V=\frac{n}{M}$, we get $V=\frac{6.00\ mol}{0.078\ mol/L}$.

Step3: Calculate volume

$V=\frac{6.00}{0.078}\ L\approx76.923\ L$. Rounding to two - significant digits (since 0.078 has two significant digits), $V = 77\ L$.

Answer:

77 L