Question

calculate the mass of h2 required to react with 98.0 g of this triglyceride. molar mass = 801.3 g/mol 9 h2 the correct answer is c51h92o6, 801.3 g/mol.

Explanation:

Step1: Calculate moles of triglyceride

The molar - mass of the triglyceride is $M = 801.3\ g/mol$. The mass of the triglyceride is $m = 98.0\ g$. The number of moles of triglyceride $n_{triglyceride}=\frac{m}{M}=\frac{98.0\ g}{801.3\ g/mol}\approx0.1223\ mol$.

Step2: Determine the mole - ratio

The reaction of hydrogenation of triglyceride involves a certain mole - ratio. Assuming a common hydrogenation reaction of triglyceride where the mole - ratio of hydrogen to triglyceride is 3:1 (since triglyceride has multiple double - bonds). So for every 1 mole of triglyceride, 3 moles of $H_2$ are required.

Step3: Calculate moles of $H_2$

If $n_{triglyceride}=0.1223\ mol$, then the number of moles of $H_2$ required $n_{H_2}=3\times n_{triglyceride}=3\times0.1223\ mol = 0.3669\ mol$.

Step4: Calculate mass of $H_2$

The molar mass of $H_2$ is $M_{H_2}=2.016\ g/mol$. The mass of $H_2$ required $m_{H_2}=n_{H_2}\times M_{H_2}=0.3669\ mol\times2.016\ g/mol\approx0.74\ g$.

Answer:

$0.74\ g$