Question

calculate the mass of aluminum hydroxide. al(oh)₃
please show all work and explain how you determined your answer
(4 points)

Explanation:

Step1: Find atomic masses

Atomic mass of Al: $26.98$ g/mol, O: $16.00$ g/mol, H: $1.008$ g/mol.

Step2: Calculate molar mass of $\ce{Al(OH)3}$

Molar mass = (1×Al) + (3×O) + (3×H) = $26.98 + 3×16.00 + 3×1.008$.
Calculate: $26.98 + 48.00 + 3.024 = 78.004$ g/mol.
(Note: If calculating mass for a specific amount, e.g., 1 mole, mass is 78.00 g (approx). If amount is given, use $mass = moles × molar\ mass$.)

Answer:

The molar mass (mass of 1 mole) of $\ce{Al(OH)3}$ is approximately $\boldsymbol{78.00\ \text{g/mol}}$. (If moles are provided, substitute into $mass = n × 78.00$ to find mass.)