Question

calculate the average atomic mass for the following situation. lithium - 6 = 7.5% and lithium - 7 = 92.5% 6.3 6.9 69.2 692.5 what is the average atomic mass for chlorine given the following analysis. chlorine - 35 = 76% and chlorine - 37 = 24% 17.2 28.5 33.5 35.5

Explanation:

Question 14 (Lithium Average Atomic Mass)

Step1: Convert percentages to decimals

Lithium - 6: \( 7.5\% = 0.075 \), Lithium - 7: \( 92.5\% = 0.925 \)

Step2: Multiply mass by decimal abundance

Lithium - 6 contribution: \( 6\times0.075 = 0.45 \)
Lithium - 7 contribution: \( 7\times0.925 = 6.475 \)

Step3: Sum the contributions

Average atomic mass: \( 0.45 + 6.475 = 6.925\approx6.9 \) (rounded appropriately)

Step1: Convert percentages to decimals

Chlorine - 35: \( 76\% = 0.76 \), Chlorine - 37: \( 24\% = 0.24 \)

Step2: Multiply mass by decimal abundance

Chlorine - 35 contribution: \( 35\times0.76 = 26.6 \)
Chlorine - 37 contribution: \( 37\times0.24 = 8.88 \)

Step3: Sum the contributions

Average atomic mass: \( 26.6 + 8.88 = 35.48\approx35.5 \) (assuming the option is presented as, for example, C. 35.5 if that was the option label; based on calculation, the value is approximately 35.5)

Answer:

6.9 (assuming the option is presented as, for example, B. 6.9 if that was the option label; based on calculation, the value is approximately 6.9)

Question 18 (Chlorine Average Atomic Mass)