Question

the box below represents the reactant atoms in blue (b) and molecules in green (g2). after reacting, these reactants form the compound pictured in the box at the right. which of the following represents the correctly balanced chemical equation for this process? 2b + 3g₂ → 2bg₃ 3b₂ + 3g → 3gb₂ 3b + 2g₂ → 2bg₂ 2b + 3g₂ → 3bg₂

Explanation:

Step1: Count the number of B atoms

In the left - hand box (reactants), count the number of blue (B) atoms. There are 6 B atoms.

Step2: Count the number of G atoms

In the left - hand box (reactants), count the number of green (G) atoms. Since each \(G_2\) molecule has 2 G atoms and there are 6 \(G_2\) molecules, the number of G atoms is \(6\times2 = 12\) G atoms.

Step3: Analyze each option for atom balance

• **Option 1: \(2B + 3G_2

ightarrow2BG_3\)**

• For B atoms: Left - hand side has \(2\) B atoms, right - hand side has \(2\) B atoms.
• For G atoms: Left - hand side has \(3\times2=6\) G atoms, right - hand side has \(2\times3 = 6\) G atoms.
• **Option 2: \(3B_2+3G

ightarrow3GB_2\)**

• The reactant side has \(B_2\) (which is not in the original reactants as B is in atomic form in the left - hand box) and \(G\) (but \(G\) is in \(G_2\) form in the left - hand box), so this option is incorrect.
• **Option 3: \(3B + 2G_2

ightarrow2BG_2\)**

• For B atoms: Left - hand side has \(3\) B atoms, right - hand side has \(2\) B atoms (not balanced).
• **Option 4: \(2B+3G_2

ightarrow3BG_2\)**

• For B atoms: Left - hand side has \(2\) B atoms, right - hand side has \(3\) B atoms (not balanced).

Answer:

\(2B + 3G_2
ightarrow2BG_3\)