Question

bellringer

1. multi-step: calculate the number of atoms in a 5.45

g sample of glucose (c₁₂h₂₂o₁₁).(grams to moles to atoms)

1. whats your favorite kind of chewing gum?

Explanation:

Step1: Calculate molar mass of glucose

The molar mass of \(C = 12.01\space g/mol\), \(H= 1.008\space g/mol\), \(O = 16.00\space g/mol\).
For \(C_{12}H_{22}O_{11}\), molar mass \(M=(12\times12.01)+(22\times1.008)+(11\times16.00)\)
\(M = 144.12+22.176 + 176\)
\(M=342.296\space g/mol\)

Step2: Calculate moles of glucose

Using the formula \(n=\frac{m}{M}\), where \(m = 5.45\space g\) and \(M = 342.296\space g/mol\)
\(n=\frac{5.45}{342.296}\approx0.0159\space mol\)

Step3: Calculate molecules of glucose

Using \(N = n\times N_A\), where \(N_A=6.022\times 10^{23}\space mol^{-1}\)
\(N=0.0159\times6.022\times 10^{23}\)
\(N = 9.575\times10^{21}\) molecules

Step4: Calculate atoms in one molecule of glucose

One molecule of \(C_{12}H_{22}O_{11}\) has \(12 + 22+11=45\) atoms

Step5: Calculate total atoms

Total atoms \(=45\times N\)
\(=45\times9.575\times 10^{21}\)
\(=4.309\times 10^{23}\) atoms

Answer:

\(4.31\times 10^{23}\) atoms