Sovi.AI - AI Math Tutor

Scan to solve math questions
ENFRDEESJAZH-CNZH-TW

QUESTION IMAGE

8. balance the equation for the reaction of potassium with water, k(s) …

Question

  1. balance the equation for the reaction of potassium with water, k(s) + h₂o(l) → h₂(g) + koh(aq)
  2. balance each of the following chemical equations.

a. na₂so₄(aq) + cacl₂(aq) → caso₄(s) + nacl(aq)
b. fe(s) + h₂o(g) → fe₃o₄(s) + h₂(g)
c. ca(oh)₂(aq) + hcl(aq) → cacl₂(aq) + h₂o(l)
d. br₂(g) + h₂o(l) + so₂(g) → hbr(aq) + h₂so₄(aq)
e. naoh(s) + h₃po₄(aq) → na₃po₄(aq) + h₂o(l)
f. nano₃(s) → nano₂(s) + o₂(g)
g. na₂o₂(s) + h₂o(l) → naoh(aq) + o₂(g)
h. si(s) + s₈(s) → si₂s₄(s)

  1. balance each of the following chemical equations.

a. nacl(s) + so₂(g) + h₂o(g) + o₂(g) → na₂so₄(s) + hcl(g)
b. br₂(l) + i₂(s) → ibr₃(s)
c. ca(s) + h₂o(g) → ca(oh)₂(aq) + h₂(g)
d. bf₃(g) + h₂o(l) → b₂o₃(s) + hf(g)
e. so₂(g) + cl₂(g) → socl₂(l) + cl₂o(g)
f. li₂o(g) + h₂o(l) → lioh(aq)
g. mg(s) + cuo(s) → mgo(s) + cu(l)
h. fe₃o₄(s) + h₂(g) → fe(l) + h₂o(g)

  1. when solid red phosphorus (p₄) is burned in air, the phosphorus combines with oxygen, producing a choking cloud of tetraphosphorus decoxide. write the balanced chemical equation for the reaction.

Explanation:

Step1: Balance potassium reaction

We have $K(s)+H_2O(l)
ightarrow H_2(g)+KOH(aq)$. First, balance potassium. Put a 2 in front of $K$ and $KOH$: $2K(s)+H_2O(l)
ightarrow H_2(g)+2KOH(aq)$. Then balance hydrogen and oxygen. Put a 2 in front of $H_2O$: $2K(s) + 2H_2O(l)
ightarrow H_2(g)+2KOH(aq)$.

Step2: Balance equation a in 9

For $Na_2SO_4(aq)+CaCl_2(aq)
ightarrow CaSO_4(s)+NaCl(aq)$, balance sodium. Put a 2 in front of $NaCl$: $Na_2SO_4(aq)+CaCl_2(aq)
ightarrow CaSO_4(s)+2NaCl(aq)$.

Step3: Balance equation b in 9

For $Fe(s)+H_2O(g)
ightarrow Fe_3O_4(s)+H_2(g)$, balance iron. Put a 3 in front of $Fe$: $3Fe(s)+H_2O(g)
ightarrow Fe_3O_4(s)+H_2(g)$. Then balance oxygen and hydrogen. Put a 4 in front of $H_2O$ and a 4 in front of $H_2$: $3Fe(s)+4H_2O(g)
ightarrow Fe_3O_4(s)+4H_2(g)$.

Step4: Balance equation c in 9

For $Ca(OH)_2(aq)+HCl(aq)
ightarrow CaCl_2(aq)+H_2O(l)$, balance chlorine. Put a 2 in front of $HCl$: $Ca(OH)_2(aq)+2HCl(aq)
ightarrow CaCl_2(aq)+H_2O(l)$. Then balance hydrogen and oxygen. Put a 2 in front of $H_2O$: $Ca(OH)_2(aq)+2HCl(aq)
ightarrow CaCl_2(aq)+2H_2O(l)$.

Step5: Balance equation d in 9

For $Br_2(g)+H_2O(l)+SO_2(g)
ightarrow HBr(aq)+H_2SO_4(aq)$, balance bromine. Put a 2 in front of $HBr$: $Br_2(g)+H_2O(l)+SO_2(g)
ightarrow 2HBr(aq)+H_2SO_4(aq)$. Then balance oxygen and hydrogen by adjusting coefficients. The balanced equation is $Br_2(g)+2H_2O(l)+SO_2(g)
ightarrow 2HBr(aq)+H_2SO_4(aq)$.

Step6: Balance equation e in 9

For $NaOH(s)+H_3PO_4(aq)
ightarrow Na_3PO_4(aq)+H_2O(l)$, balance sodium. Put a 3 in front of $NaOH$: $3NaOH(s)+H_3PO_4(aq)
ightarrow Na_3PO_4(aq)+H_2O(l)$. Then balance hydrogen and oxygen. Put a 3 in front of $H_2O$: $3NaOH(s)+H_3PO_4(aq)
ightarrow Na_3PO_4(aq)+3H_2O(l)$.

Step7: Balance equation f in 9

For $NaNO_3(s)
ightarrow NaNO_2(s)+O_2(g)$, balance oxygen. Put a 2 in front of $NaNO_3$ and a 2 in front of $NaNO_2$: $2NaNO_3(s)
ightarrow 2NaNO_2(s)+O_2(g)$.

Step8: Balance equation g in 9

For $Na_2O_2(s)+H_2O(l)
ightarrow NaOH(aq)+O_2(g)$, balance sodium. Put a 2 in front of $NaOH$. Then balance oxygen and hydrogen. The balanced equation is $2Na_2O_2(s)+2H_2O(l)
ightarrow 4NaOH(aq)+O_2(g)$.

Step9: Balance equation h in 9

For $Si(s)+S_8(s)
ightarrow Si_2S_4(s)$, balance silicon. Put a 2 in front of $Si$. Then balance sulfur. Put a 2 in front of $Si_2S_4$ and adjust the sulfur - related coefficients. The balanced equation is $4Si(s)+S_8(s)
ightarrow 2Si_2S_4(s)$.

Step10: Balance equation a in 10

For $NaCl(s)+SO_2(g)+H_2O(g)+O_2(g)
ightarrow Na_2SO_4(s)+HCl(g)$, balance sodium. Put a 2 in front of $NaCl$. Then balance sulfur, oxygen and hydrogen. The balanced equation is $4NaCl(s)+2SO_2(g)+2H_2O(g)+O_2(g)
ightarrow 2Na_2SO_4(s)+4HCl(g)$.

Step11: Balance equation b in 10

For $Br_2(l)+I_2(s)
ightarrow IBr_3(s)$, balance bromine and iodine. Put a 3 in front of $Br_2$ and a 2 in front of $IBr_3$: $3Br_2(l)+I_2(s)
ightarrow 2IBr_3(s)$.

Step12: Balance equation c in 10

For $Ca(s)+H_2O(g)
ightarrow Ca(OH)_2(aq)+H_2(g)$, balance calcium. Then balance hydrogen and oxygen. Put a 2 in front of $H_2O$: $Ca(s)+2H_2O(g)
ightarrow Ca(OH)_2(aq)+H_2(g)$.

Step13: Balance equation d in 10

For $BF_3(g)+H_2O(l)
ightarrow B_2O_3(s)+HF(g)$, balance boron. Put a 2 in front of $BF_3$. Then balance hydrogen and oxygen. Put a 3 in front of $H_2O$ and a 6 in front of $HF$: $2BF_3(g)+3H_2O(l)
ightarrow B_2O_3(s)+6HF(g)$.

Step14: Balance equation e in 10

For $SO_2(g)+Cl_2(g)
ightarrow SOCl_2(l)+Cl_2O(g)$, balance chlorine and oxygen. The balanced equation is $SO_2(g)+2Cl_2(g)
ightarrow S…

Answer:

  • $2K(s)+2H_2O(l)

ightarrow H_2(g)+2KOH(aq)$

  • $Na_2SO_4(aq)+CaCl_2(aq)

ightarrow CaSO_4(s)+2NaCl(aq)$

  • $3Fe(s)+4H_2O(g)

ightarrow Fe_3O_4(s)+4H_2(g)$

  • $Ca(OH)_2(aq)+2HCl(aq)

ightarrow CaCl_2(aq)+2H_2O(l)$

  • $Br_2(g)+2H_2O(l)+SO_2(g)

ightarrow 2HBr(aq)+H_2SO_4(aq)$

  • $3NaOH(s)+H_3PO_4(aq)

ightarrow Na_3PO_4(aq)+3H_2O(l)$

  • $2NaNO_3(s)

ightarrow 2NaNO_2(s)+O_2(g)$

  • $2Na_2O_2(s)+2H_2O(l)

ightarrow 4NaOH(aq)+O_2(g)$

  • $4Si(s)+S_8(s)

ightarrow 2Si_2S_4(s)$

  • $4NaCl(s)+2SO_2(g)+2H_2O(g)+O_2(g)

ightarrow 2Na_2SO_4(s)+4HCl(g)$

  • $3Br_2(l)+I_2(s)

ightarrow 2IBr_3(s)$

  • $Ca(s)+2H_2O(g)

ightarrow Ca(OH)_2(aq)+H_2(g)$

  • $2BF_3(g)+3H_2O(l)

ightarrow B_2O_3(s)+6HF(g)$

  • $SO_2(g)+2Cl_2(g)

ightarrow SOCl_2(l)+Cl_2O(g)$

  • $Li_2O(g)+H_2O(l)

ightarrow 2LiOH(aq)$

  • $Mg(s)+CuO(s)

ightarrow MgO(s)+Cu(l)$

  • $Fe_3O_4(s)+4H_2(g)

ightarrow 3Fe(l)+4H_2O(g)$

  • $P_4(s)+5O_2(g)

ightarrow P_4O_{10}(s)$