Question

balance the equation
nacl + f₂ → naf + cl₂

Explanation:

Step1: Balance chlorine atoms

On the left - hand side, there is \(1\) \(Cl\) atom in \(NaCl\), and on the right - hand side, there are \(2\) \(Cl\) atoms in \(Cl_2\). So, we put a coefficient of \(2\) in front of \(NaCl\).
\(2NaCl+F_2
ightarrow NaF + Cl_2\)

Step2: Balance sodium atoms

Since we have \(2\) \(Na\) atoms on the left - hand side (from \(2NaCl\)), we put a coefficient of \(2\) in front of \(NaF\) on the right - hand side.
\(2NaCl+F_2
ightarrow 2NaF + Cl_2\)

Step3: Check fluorine atoms

On the left - hand side, there are \(2\) \(F\) atoms in \(F_2\), and on the right - hand side, there are \(2\) \(F\) atoms in \(2NaF\). The equation is now balanced.

Answer:

\(2NaCl + 1F_2
ightarrow2NaF+1Cl_2\)