Question

balance the equation and calculate how many moles of o₂ form when each quantity of reactant completely reacts. n₂o₅(g) → no₂(g) + o₂(g) part d 25.0 g n₂o₅ express your answer in moles to three significant figures. part e 2.55 kg n₂o₅ express your answer in moles to three significant figures.

Explanation:

Step1: Calculate molar mass of N₂O₅

The molar mass of N₂O₅: N has an atomic mass of approximately 14 g/mol and O has an atomic mass of approximately 16 g/mol. So, \(M = 2\times14+5\times16=28 + 80=108\space g/mol\)

Step2: Convert mass to moles for 25.0 g N₂O₅

Use the formula \(n=\frac{m}{M}\), where \(m = 25.0\space g\) and \(M = 108\space g/mol\). Then \(n=\frac{25.0}{108}\approx0.231\space mol\)

Step3: Convert mass to moles for 2.55 kg N₂O₅

First convert 2.55 kg to g: \(2.55\space kg=2.55\times1000 = 2550\space g\). Then use \(n=\frac{m}{M}\), with \(m = 2550\space g\) and \(M = 108\space g/mol\). So \(n=\frac{2550}{108}\approx23.6\space mol\)

Answer:

Part D: 0.231 mol
Part E: 23.6 mol