Question

balance this equation- _secl₆+_o₂>_seo₂+_cl₂

Explanation:

Step1: Check elements on both sides

• For \(Se\): \(1\) atom on left (in \(SeCl_6\)) and \(1\) atom on right (in \(SeO_2\)).
• For \(Cl\): \(6\) atoms on left (in \(SeCl_6\)) and \(2\) atoms on right (in \(Cl_2\)).
• For \(O\): \(2\) atoms on left (in \(O_2\)) and \(2\) atoms on right (in \(SeO_2\)).

Step2: Balance \(Cl\) atoms

If we put a coefficient of \(3\) in front of \(Cl_2\), we have \(6\) \(Cl\) atoms on the right (\(3\times2 = 6\)). But let's check the options.
If we use the first option \(1,2,1,2\):

• \(Se\): \(1\) (left \(SeCl_6\)) and \(1\) (right \(SeO_2\))
• \(Cl\): \(6\) (left \(SeCl_6\)) and \(2\times3 = 6\) (right \(2Cl_2\))
• \(O\): \(2\times1 = 2\) (left \(O_2\)) and \(2\times1 = 2\) (right \(SeO_2\))

Answer:

\(1,2,1,2\)