Question

balance the chemical equation by selecting the appropriate coefficient for each substance. enter 1 if the coefficient is 1. do not leave it blank. a. b. c. fe(s) + hcl(aq)→fecl₃(aq) + h₂(g) 1. 1 2. 2 3. 3 4. 4 5. 5 6. 6 7. 7 8. 8 9. 9

Explanation:

Step1: Balance Cl atoms

On the left - hand side, we have \(HCl\) and on the right - hand side, we have \(FeCl_3\). The least common multiple of \(1\) (from \(HCl\)) and \(3\) (from \(FeCl_3\)) is \(6\). So, if we set the coefficient of \(FeCl_3\) as \(2\) (because \(2\times3 = 6\) Cl atoms on the right), then the coefficient of \(HCl\) should be \(6\) (since \(6\times1=6\) Cl atoms on the left).

Step2: Balance Fe atoms

Since the coefficient of \(FeCl_3\) is \(2\), to balance Fe atoms, the coefficient of \(Fe\) should be \(2\) (because there is \(1\) Fe atom in \(Fe\) and \(1\) Fe atom in \(FeCl_3\)).

Step3: Balance H atoms

We have \(6\) H atoms from \(6HCl\). On the right - hand side, \(H_2\) has \(2\) H atoms. Let the coefficient of \(H_2\) be \(x\). Then \(2x=6\), so \(x = 3\).

Answer:

The balanced chemical equation is \(2Fe(s)+6HCl(aq)\to2FeCl_3(aq)+3H_2(g)\). So the coefficients are \(Fe = 2\), \(HCl=6\), \(FeCl_3 = 2\), \(H_2=3\)