Question

for an aqueous solution of sucrose (c₁₂h₂₂o₁₁), calculate the molarity of 7.80 l of a solution that contains 275.0 g of sucrose. report your answer using the correct number of significant figures.

Explanation:

Step1: Calculate molar mass of sucrose

The molar mass of \(C_{12}H_{22}O_{11}\) is \(M=(12\times12 + 22\times1+11\times16)\space g/mol=(144 + 22+176)\space g/mol = 342\space g/mol\)

Step2: Calculate moles of sucrose

Using the formula \(n=\frac{m}{M}\), where \(m = 275.0\space g\) and \(M = 342\space g/mol\). So \(n=\frac{275.0\space g}{342\space g/mol}\approx0.804\space mol\)

Step3: Calculate molarity

Using the formula \(Molarity=\frac{n}{V}\), where \(n = 0.804\space mol\) and \(V=7.80\space L\). So \(Molarity=\frac{0.804\space mol}{7.80\space L}\approx0.103\space mol/L\)

Answer:

\(0.103\space M\)